how would i graph f(x)= (x+6)(2x^2-x-6)/x^2+4x-12? can you give me the steps to graphing

Question

how would i graph f(x)= (x+6)(2x^2-x-6)/x^2+4x-12?  can you give me the steps to graphing

anonymous · Answer

factor f(x) and cancel those common factors but take care of your domain.

anonymous · Answer

You should get a really simple equation with something no in your domain then it is done.

anonymous · Answer

i common factored and got (2x+3)(x+1)/(x-2)... what do i do no i know x cannot equal 2 or -6??

anonymous · Answer

where your x+1 came from?

anonymous · Answer

factorize it again, double check it plz.

anonymous · Answer

sorry x-4

anonymous · Answer

No.

anonymous · Answer

ohhhh x-2

anonymous · Answer

srry i get it now ... can you facotr with division though??

anonymous · Answer

Then what you finally got and what is the domain of your new function?

anonymous · Answer

** graph i mean

anonymous · Answer

You have to figure out the domain then do the graph.

anonymous · Answer

domain: 2x+3... x cannot = 2 and -6

anonymous · Answer

So draw a line of 2x+3 without x=2 and x=-6 points

anonymous · Answer

how... do i just find vertex and zeros???

anonymous · Answer

Could you draw a line y=2x+3?

anonymous · Answer

i got it thanks