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Mathematics 16 Online
OpenStudy (anonymous):

Multiply. (5x2 + x – 4)(x + 2)

Parth (parthkohli):

\[= \rm x(5x^2 + x - 4) + 2(5x^2 + x - 4)\]Would you be able to figure it out now?

OpenStudy (anonymous):

thats chinese to me XD

OpenStudy (anonymous):

Can u break it down kiddo?

OpenStudy (anonymous):

5x^3 + 11x^2 -2x -8

OpenStudy (anonymous):

break it down......... xD

Parth (parthkohli):

Yo sure I can.

Parth (parthkohli):

OK, so let \(\rm blah_1\), \(\rm blah_2\), \(\rm blah_3\) and \(\rm blah_4\) be some random numbers

OpenStudy (anonymous):

sorry, got kicked, new account

Parth (parthkohli):

So then,\[\rm (blah_1 + blah_2)(blah_3 + blah_4) \]is always\[\rm blah_1(blah_3 + blah_4) + blah_2(blah_3 + blah_4)\]

Parth (parthkohli):

@NewAccountFTW Welcome back

OpenStudy (anonymous):

xD

OpenStudy (anonymous):

parth u the man!

OpenStudy (anonymous):

i love the english lang in peanut style XD

OpenStudy (anonymous):

wa..wa....wa....wa...wa...wa xD

Parth (parthkohli):

.

Parth (parthkohli):

Thanks?

Parth (parthkohli):

:)

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