(x^3-3x^2+6x-18)/(x^2-4x)*(2x-4)/(x^4-3x^3)÷(x^2+2x-8)/(16-x)

Ill post a drawing to make it viewable just help me please :)

Question

(x^3-3x^2+6x-18)/(x^2-4x)*(2x-4)/(x^4-3x^3)÷(x^2+2x-8)/(16-x)

Ill post a drawing to make it viewable just help me please :)

anonymous · Answer

$$\frac{ x^3-3x2+6x-18 }{ x^2-4x }*\frac{ 2x-4 }{ x^4-3x^3}\div \frac{ x^2+2x-8 }{ 16-x^2}$$

anonymous · Answer

I know we gotta factor and stuff first dont know the rest

anonymous · Answer

hmmmm.........does this help? http://www.wolframalpha.com/input/?i=%28x^3-3x^2%2B6x-18%29%2F%28x^2-4x%29*%282x-4%29%2F%28x^4-3x^3%29%C3%B7%28x^2%2B2x-8%29%2F%2816-x%29

anonymous · Answer

haha thanks for the effort yeah ive tried this site but its like Im truly lost steps would've been clearer feel me?

anonymous · Answer

yea I'm sorry

anonymous · Answer

not your fault aha but thanks for trying to help :)

anonymous · Answer

you're welcome :)

anonymous · Answer

gimme a minute and ill sort it out for u :)

anonymous · Answer

just have to simplify right?

anonymous · Answer

uhm I have to solve

anonymous · Answer

well in directions says perform the indicatted operations and simplify completely

anonymous · Answer

yeah basically u just need to do what is indicated and simplify... did u type in the equation correctly?

anonymous · Answer

yeah I got it thanks I just factored and canceled got it ;) thanks tho for helping and yeah I did besides when I wrote it I forgot to make the last x squared.