After a certain drug is injected into a patient, the concentration c of the drug in the bloodstream is monitored. At time t is greater than or equal to 0 (in minutes since the injection), c(t)= 30t/(t^2+2)

Question

After a certain drug is injected into a patient, the concentration c of the drug in the bloodstream is monitored.  At time t is greater than or equal to 0 (in minutes since the injection), c(t)= 30t/(t^2+2)

anonymous · Answer

draw a graph of the drug concentration

what eventually happens to the concentration of drug in the bloodstream

asnaseer · Answer

Have you tried drawing the graph?

anonymous · Answer

no idk where to start

asnaseer · Answer

What restrictions are there?
Are you allowed to use a graphing calculator/application or were you asked to graph by hand?

anonymous · Answer

it just says to draw a graph but we cant use calculators on the tests

asnaseer · Answer

so the just pick some values for t, e.g.:

t=0, 2, 4, 6, 8, 10, 20, 30

and calculate the value of c(t) for each value of t and plot them on a graph

asnaseer · Answer

*so then just...

anonymous · Answer

what about for part B: what eventually happens to the concentration of drug in the bloodstream

asnaseer · Answer

Once you have plotted those points, then you should be able to answer part B by looking at the resulting curve.

anonymous · Answer

it appears that the concentration decreases  but never becomes zero

anonymous · Answer

is that right?

asnaseer · Answer

What you can say is that the concentration tends to zero as time increases.

asnaseer · Answer

It looks like it peaks in the first 2s or so and then rapidly decays towards zero after that