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zepdrix (zepdrix):
That notation doesn't make much sense.
Do they want you to evaluate f(2)? Because that would make sense :)
OpenStudy (anonymous):
yes they do
zepdrix (zepdrix):
So you just plug a 2 into every place you see an x in the problem.
Hmmm 2 is not a special reference angle. So you can't get an exact answer.
Are you allowed to use a calculator for this problem?
OpenStudy (anonymous):
sorry i typed that wrong they want just the derivative of f(x)=sinx/cosx+ 1
zepdrix (zepdrix):
Oh I see :)
Hmmm looks like we have the quotient rule.
Remember how to set up the quotient rule?\[(\frac{ u }{ v })'=\frac{ u'v-uv' }{ v^2 }\]
So in this problem:
u=sinx
v=cosx
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zepdrix (zepdrix):
Oh maybe I'm misreading it.
Is it (cosx+1) on the bottom?
OpenStudy (anonymous):
yes........
zepdrix (zepdrix):
Ok then your v=cosx + 1 :)
OpenStudy (anonymous):
ok...
zepdrix (zepdrix):
Uh ohhhh I'm getting dots :D
You confused lil sandy? :D
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