Question

rewrite as a product of linear functions, and find the zeroes of polynomialx^4 + 5x^2-36

Answer 1

=(x^2 + 9)(x^2 - 4)
= (x^2 + 9)(x + 2)(x - 2)

x^2 + 9 is prime

Answer 2

so we factor first?

Answer 3

yes
there are 2 real roots x = 2 and x = -2

the other 2 roots are complex

Answer 4

so they are all square roots?

Answer 5

x^2 + 9 = 0
x^2 = -9
x = 3i and -3i

Answer 6

thank you.

Answer 7

yw

Answer 8

where did you pull the 2 from?