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Mathematics 20 Online
OpenStudy (anonymous):

In the figure, △ABC ~ △DEF, ∡ABG ≅∡GBC, and ∡DEH ≅∡HEF. Solve for x (Will post image below) A. x = 56 1/3 B. x = 34 2/3 C. x = 25 2/3 D. x = 7/18 I think the right answer is C, is that correct?

OpenStudy (anonymous):

OpenStudy (anonymous):

wanna try it 1st

OpenStudy (anonymous):

sure, but I might be a little slow, I have a lesson going on and I got stuck on this one question, but sure I would like to try it out

OpenStudy (anonymous):

take as much time as you want, you do will make you learn

OpenStudy (anonymous):

okay, I can get the equation down to this: HE/GB = EF/BC 16/26 (simplified) is 8/13 = (x+9)/(2x+5)

OpenStudy (anonymous):

but this is where I start to get stuck

OpenStudy (anonymous):

I know you cross multiply from there

OpenStudy (anonymous):

\[\frac{ 8 }{ 13 } = \frac{ x+9 }{ 2x+5 }\] do you know how to cross multiply

OpenStudy (anonymous):

okay, from there I get 8*2x+5 = 16x+5 = 3.2 13*x+9 = 13x+9 = 1.4

OpenStudy (anonymous):

remember 8*(2x+5)

OpenStudy (anonymous):

ohh, right so it would be 16x+40 and 13x+117

OpenStudy (anonymous):

16x+40 = 13x +117 correct now?

OpenStudy (anonymous):

16x+40 16x/16+40/16 x=2.5? 13x+117 13x/13+117/13 x = 9?

OpenStudy (anonymous):

no you get one value of x

OpenStudy (anonymous):

16x+40 = 13x +117 -40 -40 16x = 13x + 77 now?

OpenStudy (anonymous):

this is where im confused

OpenStudy (anonymous):

its the same as numbers 16x = 13x + 77 -13x -13x what do you get?

OpenStudy (anonymous):

16x = 13x + 77 -13x -13x 3x + 77 3x/3 + 77/3 I get 25.66

OpenStudy (anonymous):

why the + sign?

OpenStudy (anonymous):

no, sorry meant to be equal

OpenStudy (anonymous):

lol sorry :P

OpenStudy (anonymous):

*3x = 77 3x/3 = 77/3 I get 25.66

OpenStudy (anonymous):

wait you wanted it as a fraction C. x = 25 2/3

OpenStudy (anonymous):

how did you know it was C if you didnt do the problem :P

OpenStudy (anonymous):

yeah, that was the answer I got, but I wasn't sure if I didn't it right! Thanks so much for helping me break that down! :)

OpenStudy (anonymous):

any time

OpenStudy (anonymous):

did it*

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