Question

) Determine the equation of the line passing through the points (1, 2) and (6, -4).

Answer 1

y = mx + b

can you find the slope m?

Answer 2

Use Point-Slope form.
y - y1 = m(x - x1)

You need one point and the slope.
So find slope(m):
\[m = \frac{ y2 - y1 }{ x2 - x1 } = \frac{ (-4) - 2 }{ 6 - 1 } = \frac{ -6 }{ 5 }\] Let's use point (1, 2).

So:
y - 2 = -6/5(x - 1)
Distribute. Solve for y.
y - 2 = -6/5x - 1.2
Add 2 to both sides.

y = -6/5 + 0.8

Answer 3

I meant: y = -6/5x + 0.8

Answer 4

@jazy you did a good job but 0.8 is incorrect, do you want to retry

Answer 5

Yes. (: Where did i make the first error?

Answer 6

y - 2 = -6/5(x - 1)
Distribute. Solve for y.
y - 2 = -6/5x - 1.2 ---here

Answer 7

It's supposed to be + 1.2, right? Or should it stay as a fraction?

Answer 8

its +
so now finish it

Answer 9

Okay, my bad.

y - 2 = -6/5x + 1.2
Add 2 to both sides.

y = -6/5x + 3.2

Answer 10

you got it, just be careful when multiplying ... other than that you are good at math

Answer 11

Thanks, I'll keep that in mind! (:

Answer 12

gg thanks aaalot

Answer 13

i never new i should have changed it into a decimal