Question

If f(x)= logbase6(4x^2-2x+6)find f'(x)
I think that the start of it looks like this
1/((4x^2-2x)ln6)

Answer 1

sorry just needed it written

Answer 2

so to differentiate logs
dy/dx = f'(x)/f(x)

Answer 3

so regularly you would do

differential of

4x²-2x+6

this gives

8x-2

so you get

8x-2/4x²-2x+6


but because you have base 6 i think you get