Question

how can i solve these with substitution?
x+y=12
2x+5y=27

Answer 1

solve for y in the first equation (y = -x+12) then plug into second equation:
2x + 5(-x+12) = 27

Answer 2

isolate variable onto one side and constants on the other..we get -3x = -33 so x = 11

Answer 3

@SamanthaScarecrow have you got it or i'll show you how to solve..??

Answer 4

2x + 5(-x + 12) = 27
2x - 5x + 60 = 27

-3x + 60 = 27
-3x = -33
x = 11

Answer 5

i have 2x+5(-x+12)=27 then i distributed
so i got 2x+5x+60=27 , but because there was a minus sign infront of the x in the parenthesis i don't know if i should make it 2x-5x+60=27 or if it should be 2+5x+60=27.. so if you could show me how to do it from there @Kashan i would be very grateful c:

Answer 6

check ur signs when distributing!

Answer 7

look at my work above :)

Answer 8

2x-5x+60=27

Answer 9

ohhhh! @sportegirl i see how you did it there! okay i keep getting messed up with those negatives ><
but thank you to both of you for helping me! <3

Answer 10

ur welcome :)

Answer 11

2x-5x= -3x
so,
-3x+60= 27
-3x = 27-60
-3x = -33
x= -33/ -3
x= 11

Answer 12

got it now @SamanthaScarecrow ??

Answer 13

i do c: thank you

Answer 14

no problem.. :)