Question

Write the equation of the line that passes through (2, 2) and (6, 3) in standard form.

4x + 4y = 6

x + 4y = 12

4x + 4y = –12

x – 4y = –6

Answer 1

y=mx+b. First find slope of both those points and that = m. plug in one of those points to find the value for b. once you have a complete y=mx+b equation you can then move x and y values to one side and make it standard form.

Answer 2

Let (2, 2) and (6, 3) be (x1,y1) & (x2,y2)
First find the slope
m=(y2-y1)/(x2-x1)
m=1/4
Then take any point (2, 2) or (6, 3)
(y-y1)=m(x-x1)
Then substitute the values of m & x1&y1
x-4y+6=0

Answer 3

so which one is that the last option ?

Answer 4

Yes.