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Physics 17 Online
OpenStudy (anonymous):

Vx is the velocity of a particle moving along the x-axis as shown. If x = 2.0 m at t = 1.0 s, what is the position of the particle at t = 6.0 s?

OpenStudy (anonymous):

OpenStudy (anonymous):

you need to figure out whether the acceleration is constant or not before we can help you

OpenStudy (anonymous):

the graph is up, can that help

OpenStudy (anonymous):

okay so heres what you should do first. Make an Acceleration vs. Time graph, do you know how to get acceleration from a velocity graph?

OpenStudy (anonymous):

No , I dont but I though you had to find the area of the triangles on the graph than add them up?

OpenStudy (anonymous):

I need help with explaining that.

OpenStudy (anonymous):

you are close. The area under a velocity graph doesn't give you acceleration, instead it gives you the displacement

OpenStudy (anonymous):

however, remember displacement is not the same as position, which is why you need to find the acceleration graph first beacause the acceleration changes throughout the movement of the object

OpenStudy (anonymous):

than can you please tell me how to do the displacement, I am really sorry that is what my teacher did to get the answer but i dont know how. Sorry for the trouble.

OpenStudy (anonymous):

ok so like i said earlier the area under a velocity graph gives you the displacement. so you need to find the area of the triangles and add them together

OpenStudy (anonymous):

theres a khan academy video on how to do this, you should watch it

OpenStudy (anonymous):

Alright thanks

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