You can buy DVDs at a local store fro $15.49 each. You can buy them at an online sore for $13.99 each plus $6 for shipping. How many DVDs can you buy for the same amount at the two stores?
for this problem you need to create two equations; one that represents the amount of money it would cost to buy a certain amount of movies from the store, and another that shows the money it costs to buy a certain amount of movies online.
d = 15.49 and o = 13.99 + 6?
what you need in those equations is a variable to represent the number of movies
m???
because if I buy 2 movies from the store it will be 2 * $15.49
so lets let x = the number of movies I want to buy and y is the amount of money it costs
if I buy from the store I multiply the number of movies I want to buy times the price of each movie right?
why not m and c?
that works too. m for movies and c for cash?
uhhuh ^^
so the way we can represent the price of movies at the local store is with 15.49m = c
that make sense?
*nods*
now we can make another equation that shows the price of buying movies online. Can you make that one?
i can one sec
13.99m + 6 = c
good
^^
so now the problem asks us how many movies we can buy with the same amount of money at the two stores or for what value of m will both of our equations result in the same number c
hmm can we combine them?
and since 13.99m + 6 = c and 15.49m = c we can set these equations equal to each other because we're assuming c is the same number in both
its like saying 2+2 = 4 and 1 +3 =4 so we can say that 1 + 3 = 2 + 2
29.48m + 6 = c?
oh ota, so 15.49m = 13.99m + 6
yep
^^
can you solve from here?
i think so
let me know what you get
m = 4
yep
61.96 = c
the question didnt ask for that, but yeah good job!
it bothers me if i don't solve for all variables ... sorry
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