What is the number of real solutions?
–11x^2 = x + 11
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OpenStudy (anonymous):
no one is helping?? that s a shame!
OpenStudy (anonymous):
Can you?
OpenStudy (anonymous):
Find discriminant and then use quadratic formula to find the roots of equaton
OpenStudy (anonymous):
Do you still need help with this one?
OpenStudy (anonymous):
start with
\[11x^2+x+11=0\] then use \(b^2-4ac\) and you will see that it is negative, so no real zeros
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OpenStudy (anonymous):
So that means it has no real solutions?
OpenStudy (anonymous):
since
\[b^2-4ac=1-4\times 11\times 11<0\] (aka negative) there will be no real solutions
the quadratic formula has a
\[\sqrt{b^2-4ac}\] in it, so if the inside part is negative, no real solutions
OpenStudy (anonymous):
okay , thank you. Can you also tell me how to identify 3i on a graph?
OpenStudy (anonymous):
if it is the graph of the complex plain, think of it as the point \((0,3)\)
OpenStudy (anonymous):
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