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Find polynomial p(x). Assume lead coefficient is one Degree 4, x=-1,x=2,x= i I worked it out but did not get the correct answer @precal
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f(x) = a(x-c1)(x-c2)(x-c3)(x-c4)
What you're given are the four roots of the function. We just need to rewrite them in factor forms.
For instance, x=-1 in factor form is (x-(-1))=(x+1).
x=2 would be (x-2)
But then the x=i always come in pair. (x-i) (x+i)
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Putting them together, we should have... P=(x+1)(x-2)(x+i)(x-i)
Just now realized a = 1
So I got (X+1)(x+2)(x^2+1)
Oh dang I just seen what I did ... I got the sign wrong on the 2 Thank you very much for your help.
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