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How do i find the derivative of t^2cot(t)/5
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Hmmmm you can change cot(t) to sines and cosines, but then that leaves you the product rule AND the quotient rule. Maybe we deal with cot first? We'll save the derivative off to the side, then whenever we need it we can plug it right in? :D Unless of course you already know the derivative of cotangent. It'll be a little bit of work to get through, but it simplifies nicely.
Yes i know the derivative and the produst and quotient rule
\[\frac{ t^2\cot(t) }{ 5 }\] Is this what the problem looks like? I just wanna make sure I put the 5 in the right place ^^
Yes
|dw:1350519589713:dw| Oh did you say you already know the derivative of cotangent? Did I not need to do that part then? XD heh
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