The straight line l is parallel to y + 5x = 1, and passes through the point P(2, 3). Find its x-intercept
Well, we know that the slope of the parallel line is the same as the slope of the line of the given function
5x?
we have y = -5x +1, right?
the general form of a line is y = mx+b, where m is the slope
do you get that?
yes, so to find the x intercept do we have to plug it in to the form of a line?
first we need to find the equation of the parallel line, so now that we know the slope is m =-5, and they gave us the points (2,3)... y = mx+b 3 = -5(2) +b b = 13 y = mx+b y = -5x +13 x intercept is when y=0 0 = -5x +13 -13 = -5x x = 13/5 x int. is at (13/5, 0)
oh alright, thanks for putting it in steps it really helps!
you're welcome
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