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Mathematics 18 Online
OpenStudy (anonymous):

f(x) {|x| +2, if x<0 { 2, if x > or equal to 0 What are the steps to graphing these?

terenzreignz (terenzreignz):

Ok, if x < 0, then |x| = -x, right?

OpenStudy (anonymous):

yes

terenzreignz (terenzreignz):

So your function can be replaced by f(x) = {-x + 2, x < 0 { 2 , x > 0 or x = 0 Right?

OpenStudy (anonymous):

mhm

terenzreignz (terenzreignz):

Here's the cartesian plane.|dw:1350546837684:dw|

terenzreignz (terenzreignz):

And here is the graph of y = 2 |dw:1350546933051:dw| But The function is only y = 2 for values of x which are greater than or equal to 0, so, we lose the part where x is less than 0.

terenzreignz (terenzreignz):

Here is the graph for y = -x + 2, superimposed upon the graph of y = 2 |dw:1350547104461:dw|

terenzreignz (terenzreignz):

But y = -2 + x only for values of x less than 0, so we should lose the part where x > 0 and where x = 0, so we are left with this part: |dw:1350547280188:dw| (the black part)

OpenStudy (anonymous):

oh i see now. it's just half/half of each graph. the way they put it makes it look tricky. Thanks for your help.

terenzreignz (terenzreignz):

No problem :)

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