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Mathematics 5 Online
OpenStudy (anonymous):

graph y>2x^2-4x+1

OpenStudy (anonymous):

can u graph y=2x^2-4x+1

OpenStudy (anonymous):

all i really need to figure out is what to first do i don't know how to get the x,y yet?

OpenStudy (cwrw238):

well you can plot points (x,y). an easy one is when x = 0, y = 2(0) - 4(0) + 1 = 1 so (0,1) is a point the graph will look something like a U

OpenStudy (cwrw238):

construct a table of x and y values for your plots

OpenStudy (anonymous):

OK so is it (x+0)(x+1)

OpenStudy (anonymous):

to start out

OpenStudy (cwrw238):

no get some graph paper and plot points

OpenStudy (anonymous):

ok

OpenStudy (cwrw238):

eg x y -- -- 1 -1 (2(1)^2 - 4(1) + 1} -1 7 (2(-1)^2 - 4(-1) + 1) plot another few points

OpenStudy (anonymous):

i got it

OpenStudy (cwrw238):

it will look like this link http://www.wolframalpha.com/input/?i=2x%5E2+-+4x+%2B+1+%3D+0

OpenStudy (cwrw238):

you can also find the zeros of the function by solving 2x^2 - 4x + 1 = 0

OpenStudy (cwrw238):

i don't know what algebra level you are at can you do the above operation?

OpenStudy (anonymous):

OK thanks

OpenStudy (cwrw238):

yw

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