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OpenStudy (anonymous):
Integrate 16x^3*(ln(3x))^2 Evaluate using the reduction formula-- Integral x^m(lnx)^n dx = (x^(m+1)lnx^n)/(m+1) - (n/m+1) integral x^m (lnx)^(n-1) dx for m not equal to -1 ***So what I'm wondering is will I have to substitute a "u" for 3x, and take out the 16 and move it to the other side of the integral, to use the reduction formula?
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