can someone help me figure out factoring by grouping like 2ax-7a-2bx+7b???
@ally01203 Hi, \(\huge \color{red}{\text{Welcome to Open Study}}\ddot\smile\) for such type of problems, you find what is common between first two terms, what can u take out common from 2ax-7a ?
a??
correct :) so what do u get after taking out that common ?
a (2x-7)
that is correct,do the same thing for -2bx+7b
b (-2x+7)
can u take -b common instead of b ? try it \(\huge -b(...)\)
-b(2x+7)??
when u take out -b from 7b, u get -7 so u have \(-b(2x-7)\)\ok?
ooohHH okay cool
then what? :o
so u have \(\huge a(2x-7)-b(2x-7)\) take (2x-7) common from this, what u get?
a-b(2x-7)? D:
CORRECT ! just be careful with brackets, it will be \(\huge (a-b)(2x-7)\)
woo!! is that it?
yes, thats it, u have 2 factors as a-b and 2x-7.. wasn't it easy ? :)
yep thank u much love to u :D
welcome ^_^
Join our real-time social learning platform and learn together with your friends!