can someone help me figure out factoring by grouping like 2ax-7a-2bx+7b???
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hartnn (hartnn):
@ally01203 Hi,
\(\huge \color{red}{\text{Welcome to Open Study}}\ddot\smile\)
for such type of problems, you find what is common between first two terms,
what can u take out common from 2ax-7a ?
OpenStudy (anonymous):
a??
hartnn (hartnn):
correct :)
so what do u get after taking out that common ?
OpenStudy (anonymous):
a (2x-7)
hartnn (hartnn):
that is correct,do the same thing for -2bx+7b
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OpenStudy (anonymous):
b (-2x+7)
hartnn (hartnn):
can u take -b common instead of b ?
try it
\(\huge -b(...)\)
OpenStudy (anonymous):
-b(2x+7)??
hartnn (hartnn):
when u take out -b from 7b, u get -7
so u have
\(-b(2x-7)\)\ok?
OpenStudy (anonymous):
ooohHH okay cool
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OpenStudy (anonymous):
then what? :o
hartnn (hartnn):
so u have
\(\huge a(2x-7)-b(2x-7)\)
take (2x-7) common from this, what u get?
OpenStudy (anonymous):
a-b(2x-7)? D:
hartnn (hartnn):
CORRECT !
just be careful with brackets, it will be
\(\huge (a-b)(2x-7)\)
OpenStudy (anonymous):
woo!! is that it?
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hartnn (hartnn):
yes, thats it, u have 2 factors as a-b and 2x-7..
wasn't it easy ? :)