How to solve 2X^2-4X-4=0 by completing the square. Please explain thoroughly!

Question

anonymous · Answer

first you must divide the whole equation by the leading coefficient (2)
so you get x^2-2x-2=0

then you can add the 2 to the other side
x^2-2x=2

then you take "b" (-2 from -2x in this case) and do (b/2)^2
(-2/2)^2=1

now we can add 1 to the equation IF we add it to both sides
x^2-2x+1=2+1

Now you can factor the left side and then subtract the 3 over to the left.

Does that help?

anonymous · Answer

Is it X=1+/- Root(3)

anonymous · Answer

yep!

anonymous · Answer

Thanks! I hope its right tho; it is for a project!