Question

how do you solve this system of equations
x=2y-8
4x+y=13

Answer 1

x=2 and y=5

Answer 2

how did you get that
CAN YOU DRAW IT!
pleassseee

Answer 3

2y=x+8

y=13-4x(*-2)
-2y=-26+8x

So,

2y=x+8
-2y=-26+8x

0=9x-18

9x=18

x=2

2y=x+8
2y=(2)+8
2y=10
y=5

Answer 4

Tried, and failed utterly, to do a drawing, but here's my way of going about the problem.

#1: x = 2y - 8
#2: 4x + y = 13

Now, the trick is to express x in a succinct manner. You start my manipulating the second equation:

4x + y = 13
4x = 13 - y
x = (13 - y) / 4

Now that we have successfully expressed x in terms of y, we proceed to IMPLEMENT this new expression into #1:

x = 2y - 8
(13 - y) / 4 = 2y - 8
13 - y = 4(2y - 8)
13 - y = 8y - 32
13 = 9y - 32
9y - 32 = 13
9y = 45
y = 5

With me so far? :) Good! Now that we have successfully found the value of y, we need to find the value of x. To do this, we simply apply our newly found value of y into #1:

x = 2y - 8
x = 2 * 5 - 8
x = 10 - 8
x = 2

And that is how it's done! :)

Answer 5

thanks! (:

Answer 6

yeah, I tried to be very simples buttt :]