Graph using intercepts
7x + 2y = 6

I got (0,3) and (6/7, 0) how exactly do I graph the second intercept pair (6/7, 0)?

Question

Graph using intercepts
7x + 2y = 6

I got (0,3) and (6/7, 0) how exactly do I graph the second intercept pair (6/7, 0)?

3psilon · Answer

Graph the second what?

anonymous · Answer

(6/7, 0)

anonymous · Answer

Anyone? I'm really stuck and have a lot of work to finish. I'd really appreciate some help.

hero · Answer

7x + 2y = 6

7(0) + 2y = 6
2y = 6
  y = 6/2
   y = 3

Therefore, first point is (0,3)

7x + 2(0) = 6
7x = 6
  x = 6/7

Therefore, the second point is (6/7, 0)

Graph both points on an xy, draw a line through them, then label the line with the given equation.

anonymous · Answer

But the second point isn't an actual number, it's a fraction. How do I graph (6/7, 0)?

hero · Answer

Hint: 6/7 is close to 1