Question

what is the discriminant of x^2-12x+4=0 and what are the number and roots for the equation?

Answer 1

my answer choices are:

a:Discriminant is 144; the discriminant is greater than 0 and is the perfect square, the two roots are real and rational

b: The discriminant is -128 because the discriminant is less than 0, the two roots are complex.

c:The discriminant is 160. Beacuse the discriminant is greater than 0 and isn't a perfect square.

d:The discriminant is -160. Because the discriminant is less than 0, the two roots are complex.

Answer 2

\[\text{First, find the discriminant.}\\
\ \ \ \Delta = b^2-4ac\\
\ \ \ \ \ \ =(-12)^2-4(1)(4)\\
\ \ \ \ \ \ =144-16\\
\ \ \ \ \ \ =128\\
\text{The number of roots is the degree of the polynomial, i.e. 2.}\\
\text{Since }\Delta>0\text{ the polynomial has 2 distinct real roots.}
\]

Answer 3

thanks for helping me! I already found the answer to my problem. :)