Question

Solve using law of sines A = 76°, a = 15, b = 5

Answer 1

want to try it 1st?\[\frac{ \sin A }{ a }=\frac{ \sin B }{ b }\]

Answer 2

hey i'm tyring to do this one but since they gave me only one degree i'm having problems

Answer 3

so far i got this \[15/\sin76 = 5/4.85 = c/sinC\]

Answer 4

\[\frac{ sin 76 }{ 15 }=\frac{ sin B }{ 5 }\]
solve for B

Answer 5

gonna need an inverse tham

Answer 6

angle C is 180-A-B

Answer 7

so 104?

Answer 8

but how can i find C when i only have one degree? 76?

Answer 9

hello??

Answer 10

B = 18.87

Answer 11

C = 180 - 18.87 - 76

Answer 12

how did you get 18.87?

Answer 13

sin(76)/15=sin(B)/5
sin(B)=5*sin(76)/15
B=sin^-1(5*sin(76)/15)

Answer 14

ohh ok

Answer 15

so the degree of C will be 85?

Answer 16

correct 85.13

Answer 17

now find c

Answer 18

ok

Answer 19

so c is 4.98?

Answer 20

no

Answer 21

it should be 15.4

Answer 22

but how ?

Answer 23

hold on i think ididnt find what is sinB

Answer 24

(15*sin(85))/sin(76)

Answer 25

hmm

Answer 26

A = 76°
B = 18.87°
C = 85.13°

a = 15 m
b = 5 m
c = 15.4 m

Answer 27

ok i'm going to work it out

Answer 28

got it! thank you!! :)