A spinner is divided into equal segments. Each segment is numbered and one segment is labeled with "Free Spin." Isaiah spins the spinner ten times and gets an even number one time. What is the probability that he will get an even number on the eleventh try?
The question is a little vague (in my opinion, anyway...) Do you know how many total segments? It says it is divided evenly, so all individual spin outcomes are equally likely. But it isn't clear if there are an equal number of even and odd spaces, plus one labeled "Free Spin". Also, without knowing the total number of spaces, the effect of the "Free Spin" space on the probability is hard to know.
these are the options provided... 0%, 40%, 50%, 100% and i have no clue !
100% now don't ask y
really?
okay thanks..
Well, I have to admit that I have no idea why 100% would be correct. But since we've been told "now don't ask y", I guess there's nothing else to be done :( If you had 10 spins and only got one even, I cannot imagine why you would be 100% guaranteed of an even on your 11th spin.
yeah i know:/ hey guys im lost on this assignment..."Keisha's parents want to save in her college savings account over the next years. They have to use as an initial deposit. What simple annual interest rate do they need to meet their goal? Round your answer to the nearest tenth." any help?
I'm not good at these... but also, your question has no numbers or anything... did something not paste correctly?
sorry @sophi plz No hard feelings.i'm just kidng .☺
21,000 save in college savings*, 15 years* 12,ooo initial deposit*
Which of the following shows a proportion?
Consider the work of @jack at http://tinyurl.com/n6xx9jn ---------- 5 Odd segments 1, 3, 5, 7, 9 5 Non-odd segments 2, 4, 6, 8, Free Spins from the past have no influence on future spins, so the chance is 5/10 = 50%
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