Question

factor n^2+3n-18

Answer 1

can you factorise -18?

Answer 2

what are two of these factors that sum to 3?

Answer 3

(n+6)*(n-3)

Answer 4

(n+6)(n+3)?

Answer 5

see:

n^2+3n-18 = n^2 +(+6n)+(-3n)-18

Therefore: n^2 -3n + 6n -18 = n(n-3) +6(n-3) = (n+6)(n-3)

Answer 6

The factors of −18 are
\[(±1)(±2)(±3)(±6)(±9)(±18)\]

(-3)(6)=-18
(-3)+(6)=3