Question

What is the equation of the line that passes through (12, 4) and is perpendicular to the graph of y = (-3/4) x-2?

Answer 1

so here you essentially have a 2 part problem
first you need to know what the slope of your y = (-3/4)x-2 is
then you need to write y-y1=m(x-x1) for point (12,4)
with the slope of the m being perpendicular to the slope of your equation

Answer 2

try doing a few steps, if you get stuck i'll clarify some more

Answer 3

y = (-3/4) x-2

slope = -3/4

Answer 4

Since the Lines shuld be perpen m1*m2 = -1

-3/4 * m2 = -1

m2 = 4/3

Answer 5

Using ponit Slope Form : (12,4)


y-y1=m(x-x1)


y-4 = 4/3 ( x- 12)

Nw Just Solve

Answer 6

thanks to both of you, I wish I could give both of y'all medals. This the only topic in Algebra I just CAN'T seem to understand!