What is the equation of the line that passes through (12, 4) and is perpendicular to the graph of y = (-3/4) x-2?

Question

anonymous · Answer

so here you essentially have a 2 part problem
first you need to know what the slope of your y = (-3/4)x-2 is
then you need to write y-y1=m(x-x1) for point (12,4)
with the slope of the m being perpendicular to the slope of your equation

anonymous · Answer

try doing a few steps, if you get stuck i'll clarify some more

anonymous · Answer

y = (-3/4) x-2

slope = -3/4

anonymous · Answer

Since the Lines shuld be perpen m1*m2 = -1

-3/4 * m2 = -1

m2 = 4/3

anonymous · Answer

Using ponit Slope Form : (12,4)


y-y1=m(x-x1)


y-4 = 4/3 ( x- 12)

Nw Just Solve

anonymous · Answer

thanks to both of you, I wish I could give both of y'all medals. This the only topic in Algebra I just CAN'T seem to understand!