Question

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Answer 1

\(4x^2 + 4x - 5\) ?

Use the equation editor.

To determine the number of x-intercepts (without finding them), we can use a little hack. Remember the quadratic formula?

Take the \( {+ \over -} \sqrt {b^2 - 4ac} \), plug in your numbers.

If the answer under the root is negative, you have no (real) solutions.

If the answer under the root is 0, you have only 1 solution, as \( {+ \over -} 0 = 0\).

If the answer under the root is greater than 0, you have two solutions.

Answer 2

Okay yes, this sounds right! I am having trouble remembering how I would plug my numbers into that though..

Answer 3

\[ax^2+bx+c=0\]