I've got an ACT question that I am really confused with. http://imgur.com/FY9p1 The correct answer is C. I understand how C works but I dont understand how E doesnt work. Please help :(
I think we might have ourselves an error here. ;-p \[\huge x^{-2}> y^{-2} \Rightarrow \frac{1}{x^2} > \frac{1}{y^2}\] So for a counterexample, let x and y have the same absolute value (x = 2, y = -2 or x = 3, y = -3, etc...) Then \[\huge \frac{1}{(3)^2}> \frac{1}{(-3)^2} \text{ is false! (they are equal)}\] E is not always true.
E doesn't always work... suppose x=3, y=-2... E would be false in this case.
Thanks for the help guys, I see why its not E. For the y^-2 I was trying to plug in #'s for x and y to see if E was true. I was putting in values for y in my calculator without the parentheses and getting negative numbers. Its A really mean question for ACT to throw at us.
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