Question

A and B are constants such that (x+6)/(x^2 -3x) =A/x +B/(x-3). Find A-B.

Answer 1

Again partial fractions?

Answer 2

Start with\[\rm \large {x + 6 \over x(x - 3)} = {A \over x} + {B \over x - 3}\]Multiply both sides by \(\rm x(x - 3)\) to clear the fractions out.

Answer 3

wouldn't that just make the other side more complicated?

Answer 4

No, it'd make it easier. Do what I said.

Answer 5

how would you multiply it to the other side?

Answer 6

would you get x+6=Ax-3A+Bx

Answer 7

@ParthKohli

Answer 8

so would A=-2
B=3