Create slope-intercept form with points that pass through (4,-7) and (-2,3)
Find the slope first, which would be 10/-6 or -5/3. Then what you want to do is plug it into slope intercept form. This would be: y+7=-5/3(x-4). Does that sound right?
Don't you just substitute the x and y? Shouldn't it be 7=-5/3(-4)
After it would be reduced into slope intercept form, this is what I got: y=-5/3x -1/3
I got a positive slope and positive b when i plugged in -2,3
Well?
Sorry, one second
Okay, how did you find the slope?
3-(-7) over -2-4
slope=(y2-y1)/(x2-x1)
That would equal 10/-6, correct?
Yes
which reduces to -5/3
Yup
Pick either of the two points to use our forumla to get it down to slope intercept form. The formula we will use is: y-y1=m(x-x1)
Oh what am i saying, i meant i got a positive b
Oh, okay, do you understand the process though?
Process of getting the slope or b?
for getting the entire equation. Let me show you my reasoning. Lets pick the points (4,-7). When we plug them into our equation we get y+7=-5/3(x-4). We need to reduce this now, so let us distribute the -5/3. This will get us our new equation of y+7=-5/3x+20/3. Correct so far? Now we need to get rid of the 7 on that side so lets subtract. In order to do that we need common denominatiors. So we will end up have 21-20/3. The final answer is y=-5/3x+1/3
Got my numbers mixed up before, but there it is =)
That's what I got, what I did was I picked (4,-7), substituted them for x and y, solved the equation to get b, and plugged it in to y=-5/6x+b to get y=-5/6x+1/3
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