Question

I need help solving this: 0=x(squared)+x

Answer 1

\[0=x^2+x\]
you can use quadratic equation for that.
\[{-b \pm \sqrt{b^2-4ac}} \over 2a\]
where your a=1, b=1, and c=0.

Answer 2

Thank you!

Answer 3

If you're finding what x is then:
0 = x^2 + x
0 = x(x+1) [factor out an x]
x = 0, 0=x+1
x = -1

Therefore x = -1 and 0!

Answer 4

Or you can do it that way ^^^ @Pookie12