Question

Help with math of this? Find T , 2T *sin45 = Mg

Answer 1

@Algebraic!

Answer 2

wut?

Answer 3

\[T= \frac{ Mg }{ 2 \sin 45 }\]

Answer 4

The answer says it = Mg/2 what happens to the root2 / 2

Answer 5

no idea what you're asking... tbh

Answer 6

hahha Just wanna know how they got from \[2T *\frac{ \sqrt{2} }{ 2 } = Mg \]
to\[T = \]

Answer 7

mg/2

Answer 8

idk whats happening to the root 2 over 2

Answer 9

Yeah , but I don't see how they're getting rid of the square root?

Answer 10

\[\frac{ \sqrt{2}Mg }{ 2 }\]

Answer 11

right?

Answer 12

yes

Answer 13

so, I guess you're asking:\[\sqrt{2}T =Mg\]
\[T = \frac{Mg }{ \sqrt{2}}\]
\[T = \frac{Mg }{ \sqrt{2}} \frac{ \sqrt{2} }{ \sqrt{2} }\]

Answer 14

But they got T = Mg/2 in the book that I'm using?

Answer 15

I guess it's just a typo

Answer 16

possibly.

Answer 17

maybe the answer is actually Mg/2 ... I don't know.

Answer 18

Hahah thanks I know the questions was very vague but thanks :)

Answer 19

did you want me to look the actual problem?

Answer 20

I'll draw it, or attempt to