Question

((csc y + cot y)(csc y - cot y))/csc y

Answer 1

How do I begin to simply this expression?

Answer 2

\[(a+b)(a-b)=a^2 -b^2\]
Hmmm the top is the product of conjugates. If you multiply them, they should simplify as I have described above. That is probably a good way to start at least :D

Answer 3

fisrt you break dwon like tan = sin/ cos ... get it then you cross out

Answer 4

so is the final answer csc(y) ?

Answer 5

okay so i need you to tell me what csc like is it sin/ tan . like i forgot

Answer 6

Thanks

Answer 7

@davin
it equals 1 / sin(theta)

Answer 8

i got cscy - tan^2y / cscy

Answer 9

if you remeber there is a statement for tan^2 substitute it and then u will be closer to the answer

Answer 10

hmmm. I can't figure it out. The possible answers are
-sin y

cos y

sin y

csc y

Answer 11

he he

Answer 12

Hmmmm this one's a bit of a doozy to get through D: Hopefully I did my identities correctly.