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Mathematics 13 Online
OpenStudy (anonymous):

i need answers to these i have no clue how to get them? solve for the unknowns in figures A shown below: Angle B? Bearing of line AB? Bearing of line BC? Bearing of line DA?

OpenStudy (anonymous):

please i need help before tomorrow

OpenStudy (anonymous):

where's the "figures" ???

OpenStudy (anonymous):

OpenStudy (anonymous):

in the attachment below

OpenStudy (anonymous):

do you see it

OpenStudy (anonymous):

ok.. i see it.... that arrow way on the right is pointing north?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

to find angle B, notice that the sum of all the angles in any quadrilateral is 360 degrees. so add those known angles then subtract the sum from 360 degrees ...

OpenStudy (anonymous):

since the angles are given in degree-minute-seconds, give the measure of angle B the same way.

OpenStudy (anonymous):

is angle b 360

OpenStudy (anonymous):

no... angle B = 360 - (angle A + angle D + angle C)

OpenStudy (anonymous):

121.483

OpenStudy (anonymous):

sorry @krissywatts , i have to take off now... i'll page someone for you to get this problem continued.... @lgbasallote @helder_edwin @saifoo.khan @Hero bye... :) and, yes to your last post. i think might need to convert that decimal degrees to degree-minute-second... but i'm not sure....

OpenStudy (anonymous):

saif!!! SIFU....

OpenStudy (lgbasallote):

i'm doing some teacher stuff too...can't help... i'll page someone better than me though @dpaInc

OpenStudy (anonymous):

okay

OpenStudy (saifoo.khan):

XD

OpenStudy (anonymous):

what else do i need to do? for the other angles

OpenStudy (saifoo.khan):

If i'm not wrong, bearing of AB will be 84*21'

OpenStudy (lgbasallote):

you're wrong though....too bad

OpenStudy (helder_edwin):

\[ \large \angle B=121º29' \]

OpenStudy (saifoo.khan):

hold on a sec.

OpenStudy (anonymous):

okay

OpenStudy (saifoo.khan):

I think it will be: 96º11' -84º21' = 11º50 Then: 180 - (11º50 +89º38) to get the bearing of AB

OpenStudy (anonymous):

what about BC and DA?

OpenStudy (helder_edwin):

the bearing of BC is N42º57'W

OpenStudy (anonymous):

DA?

OpenStudy (helder_edwin):

bearing of DA N11º50'W

OpenStudy (helder_edwin):

bearing of AB E11º28'N

OpenStudy (anonymous):

thanks

OpenStudy (anonymous):

i chose you as best answer cause you stayed to help:)

OpenStudy (helder_edwin):

u r welcome. and thank you the key is to draw a coordinate system on each point.

OpenStudy (anonymous):

oh okay, yeah i didn't do that guess i should have

OpenStudy (helder_edwin):

this theorem of geometry is key |dw:1350960824103:dw|

OpenStudy (anonymous):

oh wait so angle be is 121.484 correct

OpenStudy (anonymous):

B*

OpenStudy (helder_edwin):

i posted the answer for that (my first post)

OpenStudy (helder_edwin):

B=121º29'

OpenStudy (anonymous):

okay

OpenStudy (anonymous):

guess i didn't know because everyone was confused

OpenStudy (helder_edwin):

ok. good luck.

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