w^2-6w=27 I thought the answer was -3,9 but I was incorrect can someone help me

Question

w^2-6w=27  I thought the answer was -3,9 but I was incorrect can someone help me

anonymous · Answer

w^2 - 6w - 27 = 0
(x+3)(x-9) = 0

You're correct!

anonymous · Answer

when I put that answer in my online homework it said it was incorrect should I have written it like you did with the (  )

anonymous · Answer

What is the entire problem? If it's a word problem, it's likely that w represents some quantity that can't reasonably have a negative value, so the -3 would be considered an extraneous solution leaving only 9 as a correct answer.

anonymous · Answer

solving equations by factoring and problem solving

anonymous · Answer

Are you sure you're providing the exact equation from the problem?

anonymous · Answer

the problem is w^2-6w=27

anonymous · Answer

it says solve the equation

anonymous · Answer

Can you take a screenshot of the entire problem for verification purposes?

anonymous · Answer

idk how to do that sorry......

anonymous · Answer

You make it into a quadratic equation by bring the 27 over the other side. This is what it looks like:

w^2-6w-27=0

Now you factor and solve for w.

Two numbers that multiply to -27 and add up to -6 are -9 and 3. Because -9 * 3 = -27
and -9 + 3 = -6

Therefore, the factored form is:

0= (x-9)(x+3)

From this we can conclude that, x = 9, -3. This is because since the quadratic equals zero, then one of the brackets will need to be 0. This can only be if x is 9 or -3.

Therefore, x = 9, -3.

anonymous · Answer

thank you I will try to put it in again