Ask
your own question, for FREE!
Algebra
12 Online
Solve this system of equations using substitution. Put your answer in ordered pair form, (x,y). 2x+3y=9 y=2x+13
Still Need Help?
Join the QuestionCove community and study together with friends!
so there are 2x+3y=9 y=2x+13 using substitution method you need just substitute the y value from second equation in place of y inside first equation ihan solve this and will get the value of y so this will need to replace it inside second equation and you can calcule the value of x so than will get the right answer (x,y)
little help from second equation y=2x+13 so this substitute in place of y inside first equation and will get 2x+3(2x+13)=9 now just you need to solve this for x 2x+6x+39=9 8x=9-39 8x=-30 x=-30/8 x=-15/4 y=2x+13 y=2(-15/4) +13 y=-15/2 +13 y=(-15+26)/2 y=11/2 (-15/4 ,11/2)
Can't find your answer?
Make a FREE account and ask your own questions, OR help others and earn volunteer hours!
Join our real-time social learning platform and learn together with your friends!
Join our real-time social learning platform and learn together with your friends!
Latest Questions
LoverGIRL1:
In Romeo and Juliet, Romeo is a helpless romantic who falls in love very easily. He makes decisions based on his emotions instead of thinking things through
unknownnnnnn:
Just Tell Me How many times will you choose the lie before you learn it doesnu2019t protect you it only wears me down? I donu2019t need perfect.
676767:
The clock unwinds in hollow halls, Where once his laughter filled the air, Now silence drapes these empty walls, A boyu2019s love lost beyond repair.
676767:
This year ends wrapped in thoughts of you, And the new year will begin with your wishes too.
Texasroadhouse13:
I need help Find all functions \(f:\mathbb{R}\rightarrow \mathbb{R}\) such that f
Texasroadhouse13:
Prove that all non-trivial zeros of the Riemann zeta function \(\zeta (s)=\sum _{n=1}^{\infty }\frac{1}{n^{s}}\) have a real part equal to \(1/2\).
zanesafoodie:
idk if any of u are studying health, but despite what i've learned through the ye
3 hours ago
5 Replies
0 Medals
4 hours ago
7 Replies
0 Medals
9 hours ago
0 Replies
0 Medals
10 hours ago
2 Replies
0 Medals
12 hours ago
2 Replies
0 Medals
12 hours ago
1 Reply
0 Medals
13 hours ago
8 Replies
1 Medal