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how do you factor 3b^2-9b-30
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Use the factor theorem so anything that 30 can be divisible by in the positive and negative. and that equals to zero.
and then you can use synthetic or long division.
Oh ok I see. Thank you!
First remove the 3 which is common to all terms now you have 3(b^2-3b-10) now it appears that the expression in the parenthesis can now be factored.
That makes sense. But im not really sure how to factor from there
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3(b-5)(b+2). Note that the product of -5 and +2 = -10 which is needed for the last term, further note the the sum of -5 and +2 is equal to -3 which is needed in the 2nd term.
Haha, simpler your way.
And as jiji501 posted that link can be very helpful.
cool. i'll check it out!:D and thanks radar and jiji501
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