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Can you find the slope of line y + 5x = 1 ??
5
How can you tell me ??
Firstly you should write this equation in y = mx + b form. here m is the slope..
y = 5x+
How do you find b?
How ?? y + 5x = 1 Here subtract 5x from both the sides and tell me what did you get ??
y = 1/5x
I am saying to subtract and not divide...
y= -4
Hey man.. y + 5x = 1 Here subtract 5x from both the sides : y + 5x - 5x = 1 - 5x Or : y = 1 - 5x (you cannot subtract 1 and 5x as they are unlike terms)..
So, finally you will get : y = -5x + 1
oh I see but then what???
Here, now tell me what is the slope ?? Compare it with : y = mx + c and tell me what is m here in y = -5x + 1 ??
-5
Yep.. So, the line y + 5x = 1 has slope of -5.. Now tell me what can you say about the slope perpendicular to it??
5 is perpendicular to -5?
No.. Here one property you must remember : If two lines are perpendicular, then their slopes are negative reciprocals of each other....
So, if one line has slope as \(m_1\) then other line will have slope of \(-\frac{1}{m_1}\)
Getting ??
yeah but how are 2 lines reciprocal of each other if it's not a fraction?
Not two lines.. We are talking about their slopes and not the line...
If two lines are perpendicular to each other then : |dw:1351058258967:dw|
Two lines are like this and their slope is negative reciprocal of each other.. Slope is nothing but an angle which line makes with x axis..
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