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Question

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anonymous · Answer

equation of line passing through (x1,y1),(x2,y2) is $$(y-y1)/(y2-y1) =(x-x1)/(x2-x1)$$

anonymous · Answer

yep.. jus simplify it..

campbell_st · Answer

ok... do it in bits 1st

can you find the slope...?

campbell_st · Answer

ok... slope of the line is rise over run or using a formula 

$$m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$$

where 

$$x_{1} = -3, ...y_{1} = 5,....x_{2} = -9 ... and... y_{2} = 11$$

you will need to substitute into the appropriate places and do the calculator to get te slope.

campbell_st · Answer

isn't (11 -5)/(-9 - -3) = 6/-6

campbell_st · Answer

so the slope is -1

the line can be written in slope intercept form as 

y = -1x + b

then pick a point (-3, 5) substitute x = -3 and y = 5 into the equation to find b...

campbell_st · Answer

so you need to solve 

$$5 = -1 \times -3 + b$$