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Physics 14 Online
OpenStudy (anonymous):

what will be current in circuit just switch is closed?

OpenStudy (anonymous):

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OpenStudy (anonymous):

what will be amount of charge when capacitor is fully charged? calculate time constant?

OpenStudy (anonymous):

is current in circuit=v/r charge when capacitor fllly charged Qc=CV(1-e^(-5tor/CR))

OpenStudy (anonymous):

is time constant =RC

OpenStudy (vincent-lyon.fr):

At t=0, there is no pd across the capacitor, so the 20V of the generator are flet across the resistor. This implies that initial current is 20V/2000Ω = 10 mA

OpenStudy (anonymous):

time constant=RC

OpenStudy (amriju):

look when the capacitor is fully charged....current in circuit is zero...its an open circuit ( u can jst remember that at time t=0, capacitor offers 0 resistance and has charge 0..and at time t=infinite...the cap is fully charged.. and offers infinite resistance...its becomes an open circuit )...so no current flows...no potential drop across the resistance...hence p.d across the capacitor= p.d across the source thats 20...so charge= capacitance*potential diff.. thats..20*10*10^-6 units... time constant as Shafin said is RC...for this simple circuit...u dont need more...but for a complex circuit with many resistors u need to calculate net R across CAPACITOR...after short circuiting the source...and charge at time NOT= infinity is CVe^(t/RC)..if t be the time..

OpenStudy (anonymous):

It comes under Transient response of Networks At t=0, there is no pd across the capacitor so it acts as a short circuited and the whole 20V of the voltage source is across the resistor. This implies that initial current is 20V/2000Ω = 10 mA:)

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