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Mathematics 6 Online
OpenStudy (anonymous):

f(x)=.5x+4 ang g(x)=2x-8 find f(g(x)) and g(f(x)). What do you notice?

OpenStudy (anonymous):

for f(g(x)) I got x-6 for g(f(x)) I got 4x-12, I don't think that these are right...

OpenStudy (anonymous):

its 0.5?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

f(g(x))=f(2x-8)=.5(2x-8)+4 =x-4+4 =x

jhonyy9 (jhonyy9):

sorry there is 0,5 ??? ok !!!

OpenStudy (anonymous):

g(f(x))= g(0.5x+4)= 2(0.5x+4)-8= x+2-8= x-6

hartnn (hartnn):

2(0.5x+4)-8= x+8-8

OpenStudy (anonymous):

For some reason, I wrote that wrong on my paper, but right on the computer, I put down .05 again...

OpenStudy (anonymous):

What are two other functions that are like this?

hartnn (hartnn):

first, in this case , did u get f(g(x))=g(f(x)) = x ?

OpenStudy (anonymous):

I did, and normally I can do this type of problem really easily, but I just didn't get this one

hartnn (hartnn):

so f(g(x)) = g(f(x))= x implies, f(x) and g(x) are inverses of each other . another example f(x) = e^x g(x) = ln x

OpenStudy (anonymous):

In x?

hartnn (hartnn):

natural logarithm = ln

OpenStudy (anonymous):

I don't remember learning about that...

hartnn (hartnn):

then take other example : f(x) = \(x^n\) g(x) = \(\sqrt[n]x\)

OpenStudy (anonymous):

ok thank you so much, it is 3AM, and I am really tired, my brain must not be working or something like that

hartnn (hartnn):

have a good night's sleep and sweet dreams :)

OpenStudy (anonymous):

thanks, I just have a couple more problems and then finally, bed :)

hartnn (hartnn):

yeah, ask ...

OpenStudy (anonymous):

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OpenStudy (anonymous):

this mapping diagram shows how to find the value of the composite of h and k. Choose one value of x from the first numer line and explain how to find the corresponding value of h(k(x)) the first column represents k(x)=x+1, the second represents k(x), and the third represents h(k)=1/k or h(k(x))

OpenStudy (anonymous):

It should be easy, but I don't understand what is being asked...

hartnn (hartnn):

" how to find the corresponding value of h(k(x))" ... ? just follow the arrows.... let x=1 k(x)=2, following the arrow h(k(x)) = 0.5 following the arrow

OpenStudy (anonymous):

but what is it asking?

hartnn (hartnn):

the question : 'Choose one value of x from the first numer line and explain how to find the corresponding value of h(k(x))' so i chose x=1 , then following the arrows , i got h(k(x))=0.5

OpenStudy (anonymous):

So I just had to follow the arrows, I didn't have to use formulas, or multiply the functions or anything?

hartnn (hartnn):

no, just because the diagram was given, u can follow arrows and get answer, if diagram was not given, then u had to use formulas...

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

Can you help me with a word problem?

hartnn (hartnn):

i can try

OpenStudy (anonymous):

Lily has a coupon for $10 off, an ad says that there is a 5%discount off on any purchase. Suppose Lily uses the 5% discount on an item, the uses the coupon on the same item. Write the price as a function of x. Write the price as a function of x if she used the coupon first and then the discount. Find c(d(x)) and d(c(x)) Which of these is the function for coupon first? for discount first?

OpenStudy (anonymous):

I really just need help writing the functions

OpenStudy (anonymous):

I think that c(d(x))=.95x-x-10, using c for coupon first, d for discount first; and that d(c(x)) is (x-10)-9.5x

hartnn (hartnn):

5% discount on item = x-0.05x = 0.95x then $10 off --> 0.95 x -10 this is c(d(x)), ok?

OpenStudy (anonymous):

ok, so what I had just not -x

hartnn (hartnn):

yeah, now can u find d(c(x))

OpenStudy (anonymous):

It isn't (x-10)-9.5x?

hartnn (hartnn):

no, $10 off ----> x-10 5% discount = 0.95 (x-10) d(c(x)) = x-10 - 0.95 (x-10)

hartnn (hartnn):

discount first---->c(d(x))

OpenStudy (anonymous):

So (x-10)-9.5x+95

OpenStudy (anonymous):

x-9.5x+85

hartnn (hartnn):

95?, its 9.5

hartnn (hartnn):

0.95*10=9.5

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

how would I remember how to do this if it was a test question?

hartnn (hartnn):

if u understand, u don't need to remember, just practice. which part did u not understand ?

OpenStudy (anonymous):

I guess that I did understand it, Im just really bad at writing my own functions and stuff like that, I was wondering if there was an easy way to remember how to wrie them

OpenStudy (anonymous):

that is it, thanks you soooooooo much hartnn!!! :) you are amazing

OpenStudy (anonymous):

goodnight

hartnn (hartnn):

welcome and good nite :)

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