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What is the standard form equation of the line passing through (3, –2) with a slope of 3/5?
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\[y=mx+c\]You're given the slope m=3/5, and a point (x, y)=(3, -2). So substitute the point and slope into that equation and solve for C to find your intercept.
19/5
so that would be....
5x – 3y = 19
\[c=-{19 \over 5}\] So your standard form is\[y={3 \over 5}x-{19 \over 5}\]
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then multiply everything by 5 and your good. thats right.
thank you
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