Solve this equation by completing the square. 3x2 - 4x = -2
@CliffSedge ... can you help? I have to sign off... thanks!
Factor out the 3 to make the left side x^2-4x/3 to start.
Then find half of -4/3, square it, multiply it by 3 and add it to both sides. 3(x^2-4x/3) + ___ = -2 + ___
i don't know i have no idea
You don't know how to square a fraction? Or you don't know how I got to this step?
yeah i dont know how i got this step
-8/3
Alright, let's back up and look at what we're starting with. \[\large 3x^2-4x=-2\] There are a couple ways to complete the square, but I prefer to have the leading coefficient be 1, so I'm going to divide everything by 3. \[\large \rightarrow x^2-\frac{4}{3}x=-\frac{2}{3}\]
for the blank i have -8/3
3(x^2-4x/3) +-8/3= -2 + /8/3 its right
Before we go on, a little background concept on what 'completing the square' means. |dw:1351211162365:dw|
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