Question

What is the equation of a line, in general form, that passes through points (-1, 2) and (5, 2)?


y - 2 = 0
x - 2 = 0
y - x - 2 = 0

Answer 1

that's y=2.let me explain it

Answer 2

.points (-1, 2) and (5, 2)
slope m=(y2-y1)/(x2-x1)
m=(2-2)/(-1-5)=0

Answer 3

y-y1=m(x-x1)
y-2=0(x-5)
y=2

Answer 4

you have these point : x1= -1 , y1=2
and x2=5 and y2=2.... and we know that a line equation in general is : y-y1 = m (x-x1)
which m is slope of the line , and x1,y1 is one of the points (e.g first point)
and m = (y2-y1)/(x2-x1).
done! :)

Answer 5

exactly as mark_o mentioned.