Question

please help me !!

Answer 1

page 127 number 9

Answer 2

can anyone help?

Answer 3

Can you find the gradient and intercept..

Answer 4

noope

Answer 5

??

Answer 6

I'd be so happy if you could help

Answer 7

To find the gradient plug the values to this..
\[Gradient=\frac{\Delta y}{\Delta x}=\frac{\Delta y_{1}-\Delta y_{2}}{\Delta x_{1}-{\Delta x_{2}}}\]

Answer 8

okay then what

Answer 9

i cant find out the gradient :(

Answer 10

So\[Gradient=\frac{5+1}{3-0}=\frac{6}{3}=2\]

Answer 11

yep I get that bit

Answer 12

what would the y intercept be then ?

Answer 13

Now you have m in y=mx+c..Now you could clearly what the intercept is..It's the point at which y axis intersect...

Answer 14

is the y intercept 0?

Answer 15

Nope it's 5...

Answer 16

oh i see :D

Answer 17

thankyou for your help :)

Answer 18

U are welcome!!

Answer 19

sorry to bother you again! how would i rearrange this equation to make x the subject? y=1/2x+1

Answer 20

???????

Answer 21

Move x to the right side and y to the left..

Answer 22

so it would be x=1/2y+ 1 or 1/2x=y+1

Answer 23

When you move the signs change..
a = 2b + 1
-2b=-a+1

Answer 24

can you tell me the answer so i can check what ive written

Answer 25

\[x=2(y-1)\]

Answer 26

thankyou

Answer 27

No problem.. :)

Answer 28

so what would x+2y=6 making y the saubject be

Answer 29

\[x+2y=6\]\[x+2y-x=6-x\]\[2y=6-x\]\[\frac{2y}{2}=\frac{(6-x)}{2}\]\[y=\frac{(6-x)}{2}\]

Answer 30

thankyou