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7x^2y+6 (partial^2f)/(partial y^2)
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HELP PLEASE! I thought it was just 7x^2 but it says incorrect....
7x^2 would be the first partial wrt y what is the second?
14x?
no, we treat x as a constant since we are taking the partial wrt y
what is the derivative of a constant?
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you just drop the constant, don't you?
Ohhh it's 0?!
yes, you "drop" it to zero now, since we are treating x as a constant, then x^2 is a constant, and 7x^2 is a constant, so... yes it's 0 :)
Lol thank youuu!!
welcome!
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