Question

equations ,solve for x using a smart technique

Answer 1

What do you want though?

Answer 2

Good advice. I'll do that.

Answer 3

i lost connection 4 some tym sorry
\[(x-2)(x+1)(x+4)(x+7)=19\]

Answer 4

In that case, I guess I'd simplify it and start with rational root theorem.
(Or just use my graphing calculator to be really smart)

Answer 5

they dont allow calc

Answer 6

\[(x^2+5x-14)(x^2+5x+4)=19\]
let\[x^2+5x+4=a\]\[a(a-18)=19\]

Answer 7

\[a^2-18a-19=0\]

Answer 8

\[(a-19)(a+1)\]
a=19 and a=-1

Answer 9

Then do two separate quadratics . . .
I suppose that will work.

Answer 10

so\[x^2+5x+4=19,x^2+5x+4=-1\]
my answers are flying away

Answer 11

\[x^2+5x-15=0,x^2+x+5=0\]

Answer 12

\[x=error HEEEEEELP

Answer 13

last equation error\[x^2+5x+4=-1\]
\[x^2+5x+5\]
\[x=\frac{ -5\pm \sqrt{8} }{ 2 }\]